[Zope-Coders] import Zope fails
Martijn Pieters
mj@zope.com
Mon, 11 Mar 2002 18:02:05 -0500
Eh? On the Zope Trunk:
PYTHONPATH=/hom/mj/cvstrees/ZopeTrunk/lib/python python2.1
Python 2.1.2 (#1, Jan 18 2002, 18:05:45)
[GCC 2.95.4 (Debian prerelease)] on linux2
Type "copyright", "credits" or "license" for more information.
>>> import Zope
Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "/home/mj/cvstrees/ZopeTrunk/lib/python/Zope/__init__.py", line 22,
in ?
import Globals, OFS.Application, sys
File "/home/mj/cvstrees/ZopeTrunk/lib/python/Globals.py", line 23, in ?
import Acquisition, ComputedAttribute, App.PersistentExtra, os
File "/home/mj/cvstrees/ZopeTrunk/lib/python/App/PersistentExtra.py", line
14, in ?
from class_init import default__class_init__
File "/home/mj/cvstrees/ZopeTrunk/lib/python/App/class_init.py", line 14,
in ? from AccessControl.PermissionRole import PermissionRole
File "/home/mj/cvstrees/ZopeTrunk/lib/python/AccessControl/__init__.py",
line
16, in ?
import DTML
File "/home/mj/cvstrees/ZopeTrunk/lib/python/AccessControl/DTML.py", line
19,
in ?
import SecurityManagement, string, math, whrandom, random
File
"/home/mj/cvstrees/ZopeTrunk/lib/python/AccessControl/SecurityManagement.py",
line 33, in ?
from SecurityManager import SecurityManager
File
"/home/mj/cvstrees/ZopeTrunk/lib/python/AccessControl/SecurityManager.py",
line 31, in ?
authenticated=authenticated)
TypeError: this constructor takes no arguments
>>>
--
Martijn Pieters
| Software Engineer mailto:mj@zope.com
| Zope Corporation http://www.zope.com/
| Creators of Zope http://www.zope.org/
---------------------------------------------