[Zope] help! zope start failure on linux

[Chris McDonough]

Hmmmm...

As I understand it, when you start Zope's web server frontend (medusa) in an
out of the box config, it spawns seven processes (you can see the processes
and their owners by doing a ps -aux).

The first process will show its owner as the user which you use to start
Zope.  The other six processes will be owned by the "nobody" user if started
as root.  If you start Zope as a nonroot user, all of the threads will be
owned by that user.  I think :).

Make sure you have a nobody user defined in /etc/passwd.  Alternately, you
can change the user that the "nonroot" medusa processes run under by editing
the z2.py file in the root Zope installation directory (check for the line
UID='nobody' and change it to what you want).

Good luck!

- C
 
-----Original Message-----
From: Mike Salib
To: Chris McDonough
Sent: 10/16/99 10:24 PM
Subject: Re: [Zope] help! zope start failure on linux

Thanks for the quick reply. I've replicated every condition imaginable:

When I try to start zope on a high port, it only works when I'm myself
(non
root). It fails when I start zope as root.
For low ports, zope always dies on startup.

Do you know what user Zope tuurns itself into after startup as root?

I've tried using both the start script and running z2.py from the
command line.

Any ideas? Thanks a lot,
Mike

Chris McDonough wrote:

> Mike,
>
> Hi...
>
> What port are you trying to bind Zope to?  8080?  Or one under 1024?
And
> how are you starting Zope?
>
> If you're trying to bind to a port under 1024 (such as port 80),
you'll need
> to start Zope as root.
>
> - C
>
> -----Original Message-----
> From: Mike Salib
> To: zope@zope.org
> Sent: 10/16/99 9:38 PM
> Subject: [Zope] help! zope start failure on linux
>
> hi everybody,
> i'm running Zope 2 under RedHat Linux 5.2
> Every time I start Zope now, I get this error:
>
>   File "/home/mike/Zope-2.0.1-linux2-x86/z2.py", line 430, in ?
>     logger_object=lg)
>   File
"/home/mike/Zope-2.0.1-linux2-x86/ZServer/medusa/http_server.py",
> line 53
> 4, in __init__
>     self.bind ((ip, port))
>   File "/home/mike/Zope-2.0.1-linux2-x86/ZServer/medusa/asyncore.py",
> line 205,
> in bind
>     return self.socket.bind (addr)
> socket.error: (13, 'Permission denied')
>
> I'm not a unix newbie; i've been using unix for years. I know about
> basic file permission security. I've performed the following commands
> with no effect:
>
> chown nobody.nobody var
> chown nobody.nobody var/*
> chmod ago+rwx var
> chmod ago+rwx var/*
>
> I've verified that the var directory itself and all the files
contained
> therein are owned by user nobody and group nobody and that everything
is
> readable, writeable, and executable by user, group and all.
>
> I've also tried repeatedly deleting the pid files in the var
directory.
>
> I've searched the zope@zope.org mailing list archives for the last few
> months. Other people have reported this problem, but some still can't
> seem to get it working. If anyone could suggest what I'm doing wrong
> here, please do!
>
> Thanks a lot,
> Mike
>
> --
> "One World, One Web, One Program" - Microsoft Promotional Ad
> "Ein Volk, Ein Reich, Ein Fuhrer" - Adolf Hitler
>
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--
"One World, One Web, One Program" - Microsoft Promotional Ad
"Ein Volk, Ein Reich, Ein Fuhrer" - Adolf Hitler